If the length of one of the legs of a right tri-le is decreased by 10%

1.	If the length of one of the legs of a right tri-le is decreased by 10%, and the length of theangle rother leg is increased by 20%, then what is theapproximate percent change in the area of thetriangle?
Answer» Let original length of right triangle sides be B and HArea of triangle A =1/2xBxH If B decreased by 10% then length of leg= B - Bx10/100= Bx9/10 If H increased by 20% then length of leg= H + Hx20/100= Hx6/5 Area of triangle with changed dimentionsA1 = 1/2(Bx9/10)(Hx6/5)A1 = 27/50xBxH Percent change in Area of triangle = [(A1 - A) /A] x100= [(27/50XBXH - 1/2xBxH)/1/2XBXH]x100= [(2/50xBxH)/(1/2xBxH)]x100= 1/50x100= 2%

If the length of one of the legs of a right tri-le is decreased by 10%, and the length of theangle rother leg is increased by 20%, then what is theapproximate percent change in the area of thetriangle?

Answer»

Let original length of right triangle sides be B and HArea of triangle A =1/2xBxH

If B decreased by 10% then length of leg= B - Bx10/100= Bx9/10

If H increased by 20% then length of leg= H + Hx20/100= Hx6/5

Area of triangle with changed dimentionsA1 = 1/2(Bx9/10)(Hx6/5)A1 = 27/50xBxH

Percent change in Area of triangle = [(A1 - A) /A] x100= [(27/50XBXH - 1/2xBxH)/1/2XBXH]x100= [(2/50xBxH)/(1/2xBxH)]x100= 1/50x100= 2%