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If the length of E. coli DNA is 1.36 mm, then how many base pairs are present in E. coil ?A. `3.6 xx 10^(4)`B. `3.6 xx 10^(6)`C. `4.0 xx 10^(6)`D. `4.6 xx 10^(6)` |
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Answer» Correct Answer - C No. of base pair `=("Total length")/("Length between 2 bases")` `=(1.36xx10^(-3))/(0.34xx10^(-9))=4xx10^(6)` |
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