If the length of a seconds pendulum is decreased by2% find the gain or

1.	If the length of a seconds pendulum is decreased by2% find the gain or loss per day.
Answer» Solution :`T_2//T_1=sqrt(0.98l//l)T_2 = 2 xx0.9899=1.979 `Deevax in period = 0.201 second PENDULUM gains 0.0201 second in 2 second . GAIN in one DAY `= 0.0201 xx24xx60 xx60//2 = 868.32`

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