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If the kinetic energy of a particle moving with a constant speed on a circular path of radius 4 m is 100 j .Then the centripetal force will beA. 30 NB. 50 NC. 40 ND. 60 N |
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Answer» Correct Answer - B `K.E.=(1)/(2)mv^(2)=(1)/(2)((mv^(2))/(r))r=F_(r)/(2)` `therefore F=(2E)/(r)` |
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