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If the ionization energy of hydrogen is 313.8Kcal per mole, then the energy of the electron in 2nd excited state will be:-(1) 113.2 Kcal/mole (2) 78.45 Kcal/mole(3) 313.8 Kcal/mole (4) 35 Kcal/mole |
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Answer» If the ionization energy of hydrogen is 313.8Kcal per mole, then the energy of the electron in 2nd excited state will be:- (1) 113.2 Kcal/mole (2) 78.45 Kcal/mole (3) 313.8 Kcal/mole (4) 35 Kcal/mole |
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