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if the initial speed of a particle is u and its acceleration is given as a is equals to At3 where A is constant and t is time then its speed we will be given as |
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Answer» Given: f=at Where a is constant and time is t f= dV/dt=at Integrate on both sides. Limits of VELOCITY: INITIAL velocity =u Final velocity=V Time initial=0 Final time=t On INTEGRATING: dV/dt=at We get V-u= 1/2 at^2 V=u+1/2at^2 Now on sq V=u+at^4/4 HOPE IT HELPS U^_^ |
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