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If the hight of the cylinder becomes 1/4 of the orginal hight and the radius is doubled ,then the curved surface area of the new cylinder is equal to how many times the orginal cylinderplease say the correct answer . don't spame

Answer»

Step-by-step EXPLANATION:

Curved Surface area (CSA) of ORIGINAL CYLINDER

= 2 π R h

( CSA By formula )

CSA of New Cylinder = 2 π × 2r × 1/4h

= 4 π r × 1 / 4h

= π r h

CSA of Original Cylinder was / is twice the CSA of New Cylinder.



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