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If the hight of the cylinder becomes 1/4 of the orginal hight and the radius is doubled ,then the curved surface area of the new cylinder is equal to how many times the orginal cylinderplease say the correct answer . don't spame |
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Answer» Step-by-step EXPLANATION: Curved Surface area (CSA) of ORIGINAL CYLINDER = 2 π R h ( CSA By formula ) CSA of New Cylinder = 2 π × 2r × 1/4h = 4 π r × 1 / 4h = π r h CSA of Original Cylinder was / is twice the CSA of New Cylinder. |
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