1.

If the half-life of a radioisotope is 4 days, then how long would it take for 75% disitegration of the sample?

Answer»

8 days
10 days
12 days
14 days

Solution :`t_(1//2) = 4 "days", lambda = (0.693)/4 "days"^(-1)`
`N_0 = 100, N_t = 25`
Now `t = (2.303)/(lambda) log (N_0)/(N_t)`
`implies t = (2.303 xx 4)/(0.693) log (100)/(25) = (18.424)/(0.693) xx 0.301 = 8 ` days
It WOULD TAKE 8 days for 75% distintegration of the SAMPLE.


Discussion

No Comment Found

Related InterviewSolutions