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If the given figure, ABC is a right triangle right angled at A, BCED, ACFGand ABMN are squares on the sides BC, CA and AB respectively. Line segment AX ⊥ DE meets BC at Y.Show that(i) Δ MBC ≅ Δ ABD(ii) ar (BYXD) = 2 ar (Δ MBC)(iii) ar (BYXD) = ar (ABMN)(iv) Δ FCB ≅ Δ ACE(v) ar (CYXE) = 2 ar (ΔFCB)(vi) ar (CYXE) = ar (ACFG)(vii) ar (BCED) = ar (ABMN) + ar (ACFG) |
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Answer» If the given figure, ABC is a right triangle right angled at A, BCED, ACFGand ABMN are squares on the sides BC, CA and AB respectively. Line segment AX ⊥ DE meets BC at Y. Show that (i) Δ MBC Δ ABD (ii) ar (BYXD) = 2 ar (Δ MBC) (iii) ar (BYXD) = ar (ABMN) (iv) Δ FCB Δ ACE (v) ar (CYXE) = 2 ar (ΔFCB) (vi) ar (CYXE) = ar (ACFG) (vii) ar (BCED) = ar (ABMN) + ar (ACFG)
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