If the function g(x) is defined by g(x)=x200200+x199199+x198198+……..+x22+x+5, then g′(0)=………….

If the function g(x) is defined by g(x)=x200200+x199199+x198198+……

1.	If the function g(x) is defined by g(x)=x200200+x199199+x198198+……..+x22+x+5, then g′(0)=………….
Answer» If the function g(x) is defined by $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots \dots . . + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) = \dots \dots \dots \dots .$