Saved Bookmarks
| 1. |
If the function `f(x)=((e^(kx)-1)tankx)/(4x^(2)),x ne 0` `=16" "x=0` is continuous at x=0, then k= . . .A. `pm (1)/(8)`B. `pm 4`C. `pm 2`D. `pm 8` |
|
Answer» Correct Answer - D We have function `f(x) = ((e^(kx) -1)tan kx)/(4x^(2)) , x ne =0` ` 16 , x = 0` is continous at x = 0 `therefore underset( x to 0)(lim)((e^(kx)-1)tan kx)/(4x^(2)) = 16 ((0)/(0) "from")` ` rArr underset(x to 0)(lim) ((e^(kv) -1)/(kx)) ((tan kx)/(kv)) xx (k^(2))/(4) = 16` ` rArr (k^(2))/(4) = 16 rArr k^(2) = 64 rArr k - pm 8` |
|