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if the four term of an ap is thrice the first term and the second term exceeds twice the third term by 1 find a and d |
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Answer» a2+1=2(a3) a+d+1=2(a+2d) a+d+1=2a+4d -3d+1=a..........1 a4=3(a1) a+3d=3a 2a=3d 2(-3d+1)=3d -6d+2=3d 2=9d d=2/9 subs d in 1 -3d+1=a -3(2/9)+1=a a=-2/3+1 a=(-2+3)/3 a=1/3 hope it helps U....^_^ |
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