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If the force is given by `F=at+bt^(2)` with `t` is time. The dimensions of `a` and `b` areA. `[M L T^(-3)]` and `[M L T^(-4)]`B. `[M L T^(-4)]` and `[M L T^(-3)]`C. `[ M L T^(-1)]` and `[M L T^(-2)]`D. `[ M L T^(-2)]` and `[M L T^(0)]` |
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Answer» `F=at+bt^(2)` dimensions of at and `bt^(2)` are same as that of F `at=FrArra[T]=M^(1)L^(1)T^(-2)` `a=M^(1)L^(1)T^(-3)` `bt^(3)=FrArrb[T]^(2)=M^(1)L^(1)T^(-2)` `b=M^(1)L^(1)T^(-4)` |
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