If the foot of the perpendicular from point (4,3,8) on the line L1:x� – InterviewSolution

1.	If the foot of the perpendicular from point (4,3,8) on the line L1:x−al=y−23=z−b4,l≠0 is (3,5,7), then the shortest distance between the line L1 and line L2:x−23=y−44=z−55 is equal to :
Answer» If the foot of the perpendicular from point $(4, 3, 8)$ on the line $L_{1} : \frac{x - a}{l} = \frac{y - 2}{3} = \frac{z - b}{4},$ $l \neq 0$ is $(3, 5, 7),$ then the shortest distance between the line $L_{1}$ and line $L_{2} : \frac{x - 2}{3} = \frac{y - 4}{4} = \frac{z - 5}{5}$ is equal to :

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