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If the foot of the perpendicular drawn from the point (0,0,0) to the plane is (4,-2,-5) then the equation of the plane is . . .A. 4x + 2y + 5z = - 13B. 4x - 2y - 5z = 45C. 4x + 2y - 5z = 37D. 4x - 2y + 5z = - 5 |
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Answer» Correct Answer - B We have, foot of the perpendicualr drawn from the point (0,0,0) to the plane is (4,-2,-5). `:.` Direction ratios of normal to the required plane is (0-4, 0 + 2, 0 + 5 i.e., -4, 2,5) `:.` Required equation of plane passing through (4,-1,5) is `a(x - x_(1)) + b (y - y_(1)) + c (z - z_(1)) = 0` `implies (-4) (x - 4) + (-2) (y + 2) + (5) (z + 5) = 0` `implies -4x + 2y + 5z + 16 + 4 + 25 = 0` `implies 4x - 2y - 5z = 45` |
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