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if the focal length of concave mirror is 20 CM then where the object he placed so that the image is formed of same length that of the object? |
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Answer» ANSWERIt is given that,Focal lengthf=−20cmh i =3h o The image is three times the size of the OBJECT. So there are two cases.Case 1. For real imagem=− uv =−3v=3uUsing mirror’s formulaf1 = v1 + u1 −201 = 3u1 + u1 u= 3−80 cmCase 2. For virtual imagem= u−v =+3v=−3uAgain USING mirror’s formula−201 = −3u1 + u1 u= 3−40 cmThe possible VALUES of u are 3−80 cmand 3−40 cm.Explanation: I am not sure about this QUESTION |
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