If the figure , chords AB and CD of circle when produced meet at p . I

1.	If the figure , chords AB and CD of circle when produced meet at p . If angle APD = 36° and angle BCD = 25° ,than find angle ADC.
Answer» $Given \: chords \:AB \:and \:CD \:of \:circle\\ when \:produced \:meet \:at \:P .$ $\angle {APD} = 36\degree , \: \angle {BCD} = 25\degree$ $\red { To \:find \: \angle {ADC} = ? }$ $Join \: A \: and \:C \:to \: D \:and \:B \\respectively .$ $i ) In \: \triangle BCP , \\Exterior \angle {ABC} = \angle {BPC} + \angle {BCP }$ $\pink {Exterior \:angle \: at \: B \: is \:equal \:to }$ $\pink { (sum \:of \: interior \: opposite \: angles )}$ $\implies \angle {ABC} = 36\degree + 25 \degree\\= 61 \degree \: ---(1)$ $ii) Now , \angle {ADC} = \angle {ABC}$ $\pink { (Angles \:in \:same \:segment )}$ $\implies \angle {ADC} = 61 \:degree \: [ From \; (1) ]$ THEREFORE., $\red { \angle { ADC}} \green {= 61 \:degree}$ •••♪