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If the equation of a plane P, passing through the intersection of the planes, x+4y−z+7=0 and 3x+y+5z=8 is ax+by+6z=15 for some a,b∈R, then the distance of the point (3,2,−1) from the plane P is

Answer» If the equation of a plane P, passing through the intersection of the planes, x+4yz+7=0 and 3x+y+5z=8 is ax+by+6z=15 for some a,bR, then the distance of the point (3,2,1) from the plane P is


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