If the equation for the displacement of a particle moving on a circle path is given by, theta = 2t^(2)+0.5 where, theta is in radian and t is in second, then the angular velocity of the particle after 2 s is

If the equation for the displacement of a particle moving on a circle

1.	If the equation for the displacement of a particle moving on a circle path is given by, theta = 2t^(2)+0.5 where, theta is in radian and t is in second, then the angular velocity of the particle after 2 s is
Answer» `8 rad s^(-1)` `12 rad s^(-1)` `24 rad s^(-1)` `36 rad s^(-1)` Solution :Angular VELOCITY, `OMEGA=(d theta)/(DT)=6t^(2)`, At `t=2s` `omega = 6(2)^(2)=24 "rads"^(-1)`.