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If the equation`2^((2pi)/cos^(-1)x)-(a+1/2)2^((pi)/cos^(-1)x-a^2=0` has exactly one real solution the range of `a` is equal toA. `(-3, 1)`B. `(-oo,-3]`C. `[1,oo)`D. `[-3,oo)` |
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Answer» Correct Answer - B::C Let `2^((pi)/(cos^(-1)x))=timpliestge2` `:.` equation becomes `t^(2)-(a+1/2)t-a^(2)=0` has one root 2 or greater than 2 & other root less than `2impliesf(2)le0` `implies4-(a+1/2):2-a^(2)le0` `a^(2)+2a-3ge0` `(a+3)(a-1)ge0` `impliesale-3` or `age1` |
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