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If the electron configuration of an element is `1s^(2), 2s^(2), 2p^(6), 3s^(2), 3p^(2), 3d^(2), 4s^(2)`, the four electrons involved in chemical bond formation will beA. `3p^(6)`B. `3p^(6), 4s^(2)`C. `3p^(6),3d^(2)`D. `3d^(2), 4s^(2)` |
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Answer» Correct Answer - D d) The given electronic configuration shows that an element is vanadium (Z=22). It belongs to d-block of the periodic table. In transition table. In transition elements i.e., of d-block elements, electrons of ns and (n-1)d subshell take part in bond formation. |
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