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If the distance of the point `(alpha,2)`from its chord of contact w.r.t. the parabola `y^2=4x`is 4, then find the value of `alphadot` |
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Answer» Correct Answer - `1-2sqrt(2)` The chord of contact of parabola `y^(2)=4x` w.r.t. point P(h,2) is `2y=2(x+h)` `or" "x-y+h=0` Distance of this chord from point P is 4. `:." "(|h-2+h|)/(sqrt(2))=4` `rArr" "|h-1|=2sqrt(2)` `rArr" "h=1pm2sqrt(2)` `rArr" "h=1-2sqrt(2)" as for "h=1+2sqrt(2)` point lies inside parabola) |
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