If the distance between the points (4, p) and (1, 0) is 5, then p is e

1.	If the distance between the points (4, p) and (1, 0) is 5, then p is equal to(A) +4(B) 4(C) -4(D) 0
Answer» Answer: here we APPLY DISTANCE FORMULA that is D=√[(x2-x1)^2 + (y2-y1)^2] 5=√[(1-4)^2 + (0-p)^2] 5= √[9+p^2] 25=9+p^2 25-9=p^2 16=p^2 4=p

If the distance between the points (4, p) and (1, 0) is 5, then p is equal to(A) +4(B) 4(C) -4(D) 0

Answer»

Answer:

here we APPLY DISTANCE FORMULA that is

D=√[(x2-x1)^2 + (y2-y1)^2]

5=√[(1-4)^2 + (0-p)^2]

5= √[9+p^2]

25=9+p^2

25-9=p^2

16=p^2

4=p

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If the distance between the points (4, p) and (1, 0) is 5, then p is equal to(A) +4(B) 4(C) -4(D) 0​

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If the distance between the points (4, p) and (1, 0) is 5, then p is equal to(A) +4(B) 4(C) -4(D) 0