If the distance between the plane x−2y+z=d and the plane containing – InterviewSolution

1.	If the distance between the plane x−2y+z=d and the plane containing the lines x−12=y−23=z−34 and x−23=y−34=z−45 is √6, then \|d\| is:
Answer» If the distance between the plane $x - 2 y + z = d$ and the plane containing the lines $\frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4}$ and $\frac{x - 2}{3} = \frac{y - 3}{4} = \frac{z - 4}{5}$ is $\sqrt{6}$ , then $\| d \|$ is:

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