If the distance between the centres of the atoms of potassium and bromine in KBr (potassium - bromide) molecule is 0.282xx10^(-9)m, find the centre of mass of this particle system from potassium (mass of bromine = 80 u, and of potassium = 39 u).

If the distance between the centres of the atoms of potassium and brom

1.	If the distance between the centres of the atoms of potassium and bromine in KBr (potassium - bromide) molecule is 0.282xx10^(-9)m, find the centre of mass of this particle system from potassium (mass of bromine = 80 u, and of potassium = 39 u).
Answer» Solution :Mass of bromine, `m_(Br)=80` units Mass of potassium, `m_(K)=39`units POSITION co-ordinate of potassium, `x_(k)=0` Position co-ordinate of bromine, `x_(Br)=0.282xx10^(-9)m` `:.` Position co-ordinate of CENTRE of mass, `x_(c)=(m_(k)x_(k)+m_(Br)x_(Br))/(m_(k)+m_(Br))` `x_(c)=(39xx0+80xx0.282xx10^(-9))/(39+80)` `impliesx_(c)=0.189xx10^(-9)m`