1.

If the displacement of a particle executing SHM, is given by y=0.30 sin (220t+0.64) in metre, then the frequency and the maximum velocity of the particle are (t is in seconds)…………….

Answer»

35 Hz, 66 m/s
45 Hz, 66 m/s
58 Hz, 113 m/s
35 Hz, 132 m/s

Solution :FREQUENCY `F=(omega)/(2pi)=(220)/(6.28)=35Hz`
Maximum particle VELOCITY `v_(max)=Aomega=0.30xx220=66m//s`


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