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if the displacement of a particle after t seconds is given by s=2t^3-3t^2+2,find position,velocity and acceleration at the end of 2 seconds. |
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Answer» 3t^2+2s=16-12+2=6v=ds/dt= 6t^2-6tv=24-12=12a=dv/dt = 12t-6a=24-6=18 |
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