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If the diameter of cross-session of a wire is decreased by 5%, how much profit will thelength be increased so that volume remains the same. |
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Answer» Diametre be dradius be d/2vol=πr*r*h =πd*d*h/4if d is increased by 5% then d- 5%of dd-5/100*dd-d/2019d/20∴r=2*19d/20=19d/40vol=πd*d*h/4π*19d/40*19d/40*h∴h=400d/361 ( calculate the above one)increase in length=400h/361-l=39l/361%of increase =39h/361/h*100=3900/361% =10.80% |
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