If the determinant ∣∣∣∣∣1+sin2θsin2θsin2θcos2θ1+cos2θcos2θ4sin4θ4sin4θ1+4sin4θ∣∣∣∣∣=0, then sin4θ equals to(where θ∈[0,2π])

If the determinant ∣∣∣∣∣1+sin2θsin2θsin2θcos2θ1+cos2θco

1.	If the determinant ∣∣∣∣∣1+sin2θsin2θsin2θcos2θ1+cos2θcos2θ4sin4θ4sin4θ1+4sin4θ∣∣∣∣∣=0, then sin4θ equals to(where θ∈[0,2π])
Answer» If the determinant $∣ ∣∣∣ ∣ \begin{matrix} 1 + {sin}^{2} θ & {sin}^{2} θ & {sin}^{2} θ {cos}^{2} θ & 1 + {cos}^{2} θ & {cos}^{2} θ 4 sin 4 θ & 4 sin 4 θ & 1 + 4 sin 4 θ \end{matrix} ∣ ∣∣∣ ∣ = 0$ , then $sin 4 θ$ equals to $(where θ \in [0, 2 π])$