1.

If the de broglie wavelength of a particle of mass m is 100 times its velocity then its value in terms of its mass and planck's constant is

Answer»

Final ANSWER : 10\sqrt{\frac{h}{m}}

Steps:
1) Magnitude :
\lambda = 100 v \\ => v = \frac{\lambda}{100}

2) We KNOW by,
De-Brogie RELATION:
\lambda = \frac{h}{mv} \\ =>\lambda = \frac{h}{m \frac{\lambda}{100}} \\ => \lambda^2 = \frac{100h}{m} \\ => \lambda =10 \sqrt{\frac{h}{m}}

Hence, We got Wavelength of particle as :
\boxed{ \lambda = 10 \sqrt{ \frac{h}{m} } \: units }


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