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IF the de-Brogile wavelength of a proton is `10^(-13)m`, the electric potential through which it must have been accelerated isA. `4.07xx10^(4)V`B. `8.15xx10^(4)V`C. `8.15xx10^(3)V`D. `4.07xx10^(5)V` |
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Answer» Correct Answer - 2 `lamda_(p)=0.286/sqrtV` `lamda_(p)=10^(-13)m=10^(-3)Å` `10^(-3)=0.286/sqrtV` `rArrV=(0.286)^(2)xx10^(6)` `=0.0817xx10^(6)` `rArr8.15xx10^(4)` volt |
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