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If the curve `y=ax^(1//2)+bx` passes through the point (1,2) and lies above the x-axis for `0lexle9` and the area enclosed by the curve, the x-axis, and the line x=4 is 8 sq. units. ThenA. `a=1`B. `b=1`C. `a=3`D. `b=-1` |
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Answer» Correct Answer - C::D Since the curve `y=ax^(1//2)+bx` passes through the point (1,2) `therefore" "2=a+b" (1)"` By observation the curve also passes through (0,0). Therefore, the area enclosed by the curve, x-axis and x=4 is given by `A=overset(4)underset(0)int(ax^(1//2)+bx)dx=8 or (2a)/(3)xx8+(b)/(2)xx16=8` `or (2a)/(3)+b=1." (2)"` Solving (1) and (2), we get a =3, b=-1. |
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