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If the current is halved in a coil, then the energy stored is how much times the previous valueA. `(1)/(2)`B. `(1)/(4)`C. `2`D. `4` |
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Answer» Correct Answer - B `U=(1)/(2)Li^(2)i.e.(U_(2))/(U_(1))=((i_(2))/(i_(1)))^(2)=((1)/(2))^(2)=(1)/(4)` `impliesU_(2)=(1)/(4)U_(1)` |
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