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If the complex number z=x+iy satisfies the condition (z+1)=1 , then z lies on |
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Answer» ANSWER : CIRCLE with CENTRE (-1,0) and radius 1 Explanation : |z+1|=1|z+1|=1 |(x+1)+iy|=1|(x+1)+iy|=1 (x+1)2+y2=12(x+1)2+y2=12 Which is a Circle with centre (-1,0) and radius 1 .hope this help |
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