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If the complex number z = x + iy satisfies the condition |z +1| = 1 , then z lies on(A) x-axis(B) circle with centre (1, 0) and radius 1(C) circle with centre (–1, 0) and radius 1(D) y-axis |
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Answer» Answer is (C), |z +1|=1 ⇒ |(x +1)+iy| = 1 ⇒ (x +1)2 + y2 = 1 which is a circle with centre (–1, 0) and radius 1. |
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