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If the common difference of an ap is-6 then what is a16-a12 |
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Answer» Answer: here, common difference (d)= -6 first TERM = a [supposition] 16th term = a+ (16-1) × d= a + 15d 12th term = a + (12-1) × d = a + 11d = (a +15d) - (a + 11d) = a + 15d - a - 11d = 4d = 4× (-6) = -24 |
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