If the circle x2 + y2 + ax + by – 12 = 0 has the centre at (2, 3) th

1.	If the circle x2 + y2 + ax + by – 12 = 0 has the centre at (2, 3) then find a, b and the radius of the circle.
Answer» Equation of the circle is x² + y² + ax + by – 12 = 0 Centre = (-a/2, -b/2) = (2, 3) −a/2 = 2, − b/2 = 3 a = – 4, b = – 6 g = –2, f = –3, c = –12 radius = √(g²+ f² - c) = √(4 + 9 + 12) = 5

If the circle x2 + y2 + ax + by – 12 = 0 has the centre at (2, 3) then find a, b and the radius of the circle.

Answer»

Equation of the circle is x² + y² + ax + by – 12 = 0

Centre = (-a/2, -b/2) = (2, 3)

−a/2 = 2, − b/2 = 3

a = – 4, b = – 6

g = –2, f = –3, c = –12

radius = √(g²+ f² - c) = √(4 + 9 + 12) = 5

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If the circle x2 + y2 + ax + by – 12 = 0 has the centre at (2, 3) then find a, b and the radius of the circle.

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