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If the chord joining the points `t_1`and `t_2` on the parabola `y^2 = 4ax` subtends a right angle at its vertex then `t_2=` |
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Answer» Correct Answer - B The equation of the chord joining points `(at_(1)^(2), 2at_(1))"and"(at_(2)^(2), 2at_(2))` is `y(t_(1)+t_(2))=2x+2at_(1)t_(2)" ...(i)"` It is given that the axis i.e. y = 0, directrix x= -a and (i0 are concurrent. Therefore, chord (i) passes through the point of intersection of axis y = 0 adn directrix x= -a i.e. the point (-a, 0). `:." "-2a+2at_(1)t_(2)=0rArrt_(1)t_(2)=1` |
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