1.

If the centre of parallelopiped formed by −−→PA=2^i−^j+^k,−−→PB=−4^i+2^j−^k,−−→PC=−2^i−^j+2^k is given by position vector 3^i−2^j−2^k, then the position vector of point P is

Answer»

If the centre of parallelopiped formed by PA=2^i^j+^k,PB=4^i+2^j^k,PC=2^i^j+2^k is given by position vector 3^i2^j2^k, then the position vector of point P is



Discussion

No Comment Found

Related InterviewSolutions