1.

If the bond energies of H−H, Br−Br and H−Br are 433, 192 and 364 kJmol−1 respectively, the ΔH∘ for the reaction: H2(g)+Br2(g)→2HBr(g) is:

Answer»

If the bond energies of HH, BrBr and HBr are 433, 192 and 364 kJmol1 respectively, the ΔH for the reaction:
H2(g)+Br2(g)2HBr(g) is:



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