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If the average of (1, 8 and 9), (12, 0 and a) and (5, b and 9) is c, 5 and 7 respectively. Find the value of (2a + 5b – c).1). 402). 203). 304). 35 |
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Answer» AVERAGE = sum of elements/number of elements Given, The average of (1, 8 and 9), (12, 0 and a) and (5, B and 9) is c, 5 and 7 respectively = ⇒ (1 + 8 + 9)/3 = c ⇒ c = 18/3 ⇒ c = 6 ⇒ (12 + 0 + a)/3 = 5 ⇒ (12 + a) = 15 ⇒ a = 15 – 12 = 3 ⇒ a = 3 ⇒ (5 + b + 9)/3 = 7 ⇒ (14 + b) = 21 ⇒ b = 21 – 14 = 7 ⇒ b = 7 The value of (2a + 5b – c) = = (2 × 3 + 5 × 7 – 6) = 6 + 35 – 6 = 35 ∴ The value of (2a + 5b – c) is 35. |
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