1.

If the average of (1, 8 and 9), (12, 0 and a) and (5, b and 9) is c, 5 and 7 respectively. Find the value of (2a + 5b – c).1). 402). 203). 304). 35

Answer»

AVERAGE = sum of elements/number of elements

Given,

The average of (1, 8 and 9), (12, 0 and a) and (5, B and 9) is c, 5 and 7 respectively =

⇒ (1 + 8 + 9)/3 = c

⇒ c = 18/3

⇒ c = 6

⇒ (12 + 0 + a)/3 = 5

⇒ (12 + a) = 15

⇒ a = 15 – 12 = 3

⇒ a = 3

⇒ (5 + b + 9)/3 = 7

⇒ (14 + b) = 21

⇒ b = 21 – 14 = 7

⇒ b = 7

The value of (2a + 5b – c) =

= (2 × 3 + 5 × 7 – 6)

= 6 + 35 – 6

= 35

∴ The value of (2a + 5b – c) is 35.


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