If the area of an equalateraltriangle is 81√3 cm²

1.	If the area of an equalateraltriangle is 81√3 cm²
Answer» s not given what is to be found, however area of equilateral ∆ = 81√3 SQ cm √3/4 (SIDE)^2 = 81√3 side^2 = 81√34/√3 side^2 = 814 side = √814 = 92 side = 18 cm perimeter of triangle = 3(side) = 318 = 54 again, area of ∆ = 81√3 (1/2) x base x height = 81√3 (1/2) x 18 x height = 81√3 9 x height = 81√3 height = 81√3/9 height = 9√3 The question must be to find ONE of the above three I guess.

Answer»

s not given what is to be found, however

area of equilateral ∆ = 81√3 SQ cm

√3/4 (SIDE)^2 = 81√3

side^2 = 81√3*4/√3

side^2 = 81*4

side = √81*4

= 9*2

side = 18 cm

perimeter of triangle = 3*(side)

= 3*18

= 54

again,

area of ∆ = 81√3

(1/2) x base x height = 81√3

(1/2) x 18 x height = 81√3

9 x height = 81√3

height = 81√3/9

height = 9√3

The question must be to find ONE of the above three I guess.

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