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IF the area of a rhombus is 96 sq.cm and one of its diagonal is16 centimeter, find its perimeter. |
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Answer» Let construct a rhombus with diagonal of 16 cm and d2 Area = 1/2 × d1 × d2 96 cm^2 = 1/2 × 16 cm × d2 96 cm^2 = 8 cm × d2 96 cm^2 / 8 cm = d2 12 cm = d2 Now half the diagonals to make a small triangle AOB 16/2 = 8 cm12/2 = 6 cm h^2 = b^2 +p^2h2 = 8^2+6^2h2=100h= root 100h =10 cm |
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