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If the area of a rectangle is 93.6 m and the width is 3.6 m, then find the perimeter of the rectangle. |
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Answer» Area of rectangle = 93.6 m2 breadth = 3.6 m Area of rectangle = l x b ⇒ 93.6 = l x 3.6 ∴ l = 93.6 ÷ 3.6 = 936/10 ÷ 36/10 = 936/10 x 10/36 = 936/36 = 26 m Perimeter of rectangle 2(l + b) = 2 (26 + 3.6) = 2 x 29.6 = 59.2 m |
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