If the area of a rectangle is 1260 cm2 and its perimeter 146 cm what i

1.	If the area of a rectangle is 1260 cm2 and its perimeter 146 cm what isO 28 cm0 44 cm53 cm45 cm
Answer» ✬ LENGTH & Breadth = 45 cm , 28 cm ✬ Step-by-step EXPLANATION: Given: Area of rectangle is 1260 cm². Perimeter of rectangle is 146 cm. To Find: What is its length of breadth ? Solution: LET the length be l and breadth be b. As we know that ★ Ar. of rectangle = Length × Breadth ★ ★ Perimeter = 2(Length + Breadth) ★ A/q Perimeter = 146 cm $\implies{\rm }$ 2(l + b) = 146 $\implies{\rm }$ l + b = 146/2 $\implies{\rm }$ l + b = 73 $\implies{\rm }$ l = 73 – b........i Now, Area = 1260 cm² $\implies{\rm }$ l × b = 1260 $\implies{\rm }$ (73 – b) × b = 1260 $\implies{\rm }$ 73b – b² = 1260 $\implies{\rm }$ 0 = b² – 73b + 1260 Using middle term splitting method ➯ b² – 73b + 1260 ➯ b² – 45b – 28b + 1260 ➯ b(b – 45) – 28(b – 45) ➯ (b – 28) (b – 45) ➯ b = 28 or b = 45 Taking the first value of b. Length = 73 – b = 73 – 28 = 45 cm Breadth = 28 cm

If the area of a rectangle is 1260 cm2 and its perimeter 146 cm what isO 28 cm0 44 cm53 cm45 cm

Answer»

✬ LENGTH & Breadth = 45 cm , 28 cm ✬

Step-by-step EXPLANATION:

Given:

To Find:

Solution: LET the length be l and breadth be b.

As we know that

★ Ar. of rectangle = Length × Breadth ★

★ Perimeter = 2(Length + Breadth) ★

A/q

$\implies{\rm }$ 2(l + b) = 146

$\implies{\rm }$ l + b = 146/2

$\implies{\rm }$ l + b = 73

$\implies{\rm }$ l = 73 – b........i

Now,

$\implies{\rm }$ l × b = 1260

$\implies{\rm }$ (73 – b) × b = 1260

$\implies{\rm }$ 73b – b² = 1260

$\implies{\rm }$ 0 = b² – 73b + 1260

Using middle term splitting method

➯ b² – 73b + 1260

➯ b² – 45b – 28b + 1260

➯ b(b – 45) – 28(b – 45)

➯ (b – 28) (b – 45)

➯ b = 28 or b = 45

Taking the first value of b.