If the angular momentum of the body is increased by 50%, its rotational kinetic energy is increased by …………

If the angular momentum of the body is increased by 50%, its rotationa

1.	If the angular momentum of the body is increased by 50%, its rotational kinetic energy is increased by …………
Answer» `125%` `50%` `100%` `25%` Solution :`K=(L^(2))/(2I)` here 2I = constant `therefore KalphaL^(2)` `therefore (K_(2))/(K_(1))=((L_(2))/(L_(1)))^(2)` but 50% of `L_(2)+L_(1)` `=L_(1)+0.5L_(1)` `therefore (K_(2))/(K_(1))=((3)/(2))^(2)=(3)/(2)L_(1)` `therefore (K_(2))/(K_(1))=(9)/(4)` `therefore (K_(2)-K_(1))/(K_(1))XX100=(9-4)/(4)xx100%` `therefore (K_(2)-K_(1))/(K_(1))xx100=(5)/(4)xx100=125%`