. If the angles of a triangle are in ratio 2: 1: 3, then find measure

1.	. If the angles of a triangle are in ratio 2: 1: 3, then find measure of smallest angle.
Answer» $\huge{ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{࿐SoLuTiOn࿐}}}}}}$ $= 2 \ratio1 \ratio3$ LET the ANGLES be x $\therefore2x \ratio1x \ratio3x$ Total of all ANGELS of a TRIANGLE is 180° $\angle \: a + \angle \: b + \angle \: c = 18 {0}^{0}$ $2x + x + 3x = 180 {}^{0}$ $6x = 180 {}^{0}$ $x = \frac{180 {}^{0} }{6}$ $x = 30 {}^{0}$ ㅤ $\therefore2x = 2(30 {}^{0} ) = 60 {}^{0}$ $\therefore \: 1x = 1(30 {}^{0} ) = 30 {}^{0}$ $\therefore3x = 3(30 {}^{0} ) = 90 ^ {0}$ ㅤ $\therefore \: smallest \: angle = 30 {}^{0}$