1.

If the angle of the projection make Double with keeping same velocity of projection then find the final range?

Answer»

Explanation:

We know MAXIMUM height of a PROJECTILE motion is given by

H =

2g

v

2

sin

2

θ

Thus from the relation we can say maximum height of the projectile motion depends on squre of VELOCITY of the projectile directly.

Thus doubling the velocity will quadraple the maximum height if the angle of projectile REMAINS same.



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