1.

If the accelaration due to gravity becomes 4 times its original value, then escape speed

Answer»

REMAINS same
2 TIMES of original value
becomes halved
4 times of original value

Solution :Escapespeed4 times of .g.
`v_(e ) = sqrt(2(4g)R_(E)) = sqrt(4)xxsqrt(2g R_(E))`
`v_(e)=sqrt(2g R_(E)) , v_(e) = 2v_(e)`


Discussion

No Comment Found