Saved Bookmarks
| 1. |
If the 9th term of an A.P. is zero then show that the 29th term is twice the 19n term |
|
Answer» Let a and d respectively be the first term and common difference of the AP. Given a9= 0 So, a + (9-1)d = 0 a+8d=0 a= -8d Now, 29th term = a+28d =-8d+28d = 20d = 2 x 10d = 2(-8d + 18d) =2(a+18d) = 2 x 19th term Thus, the 29th term of the AP is twice the 19th term. please like the solution 👍 ✔️ |
|